## [HDU_ACM_Steps]Chapter One Section One

蓝飞 | 时间：2012-07-23, Mon | 11,874 views**编程算法**

### A+B for Input-Output Practice (I)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 13098 Accepted Submission(s): 6187

#### Description

Your task is to Calculate a + b.

Too easy?! Of course! I specially designed the problem for acm beginners.

You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.

#### Input

The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.

#### Output

For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

#### Sample Input

1 5 10 20

#### Sample Output

6

30#include<stdio.h> int main(){ int a, b; while(~scanf("%d%d", &a, &b)) printf("%d\n", a + b); return 0; }## A+B for Input-Output Practice (II)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 7593 Accepted Submission(s): 5398## Description

Your task is to Calculate a + b.

## Input

Input contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line.

## Output

For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

## Sample Input

2 1 5 10 20## Sample Output

6

30#include<stdio.h> int main(){ int a, b, t; scanf("%d", &t); while(t--){ scanf("%d%d",&a, &b); printf("%d\n", a + b); } return 0; }## A+B for Input-Output Practice (III)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 8870 Accepted Submission(s): 5142## Description

Your task is to Calculate a + b.

## Input

Input contains multiple test cases. Each test case contains a pair of integers a and b, one pair of integers per line. A test case containing 0 0 terminates the input and this test case is not to be processed.

## Output

For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

## Sample Input

1 5 10 20 0 0## Sample Output

6

30#include<stdio.h> int main(){ int a, b, t; while(~scanf("%d%d", &a, &b) && a || b) printf("%d\n", a + b); return 0; }## A+B for Input-Output Practice (IV)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 7942 Accepted Submission(s): 4814## Description

Your task is to Calculate the sum of some integers.

## Input

Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.

## Output

For each group of input integers you should output their sum in one line, and with one line of output for each line in input.

## Sample Input

4 1 2 3 4 5 1 2 3 4 5 0## Sample Output

10

15#include<stdio.h> int main(){ int t, num, sum; while(~scanf("%d", &t) && t){ sum = 0; while(t--){ scanf("%d", &num); sum += num; } printf("%d\n", sum); } return 0; }## A+B for Input-Output Practice (V)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 6184 Accepted Submission(s): 4653## Description

Your task is to calculate the sum of some integers.

## Input

Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.

## Output

For each group of input integers you should output their sum in one line, and with one line of output for each line in input.

## Sample Input

2 4 1 2 3 4 5 1 2 3 4 5## Sample Output

10

15#include<stdio.h> int main(){ int n, t, num, sum; scanf("%d", &t); while(t--){ sum = 0; scanf("%d", &n); while(n--){ scanf("%d", &num); sum += num; } printf("%d\n", sum); } return 0; }## A+B for Input-Output Practice (VI)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 6284 Accepted Submission(s): 4538## Description

Your task is to calculate the sum of some integers.

## Input

Input contains multiple test cases, and one case one line. Each case starts with an integer N, and then N integers follow in the same line.

## Output

For each test case you should output the sum of N integers in one line, and with one line of output for each line in input.

## Sample Input

4 1 2 3 4 5 1 2 3 4 5## Sample Output

10

15#include<stdio.h> int main(){ int n, num, sum; while(~scanf("%d", &n)){ sum = 0; while(n--){ scanf("%d", &num); sum += num; } printf("%d\n", sum); } return 0; }## A+B for Input-Output Practice (VII)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 6634 Accepted Submission(s): 4496## Description

Your task is to Calculate a + b.

## Input

The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.

## Output

For each pair of input integers a and b you should output the sum of a and b, and followed by a blank line.

## Sample Input

1 5 10 20## Sample Output

6

30

#include<stdio.h> int main(){ int a, b; while(~scanf("%d%d", &a, &b)) printf("%d\n\n", a + b); return 0; }## A+B for Input-Output Practice (VIII)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 13966 Accepted Submission(s): 4508## Description

Your task is to calculate the sum of some integers.

## Input

Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.

## Output

For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.

## Sample Input

3 4 1 2 3 4 5 1 2 3 4 5 3 1 2 3## Sample Output

10

15

6

#include<stdio.h> int main(){ int t, n, num, sum; scanf("%d", &t); while(t--){ sum = 0; scanf("%d", &n); while(n--){ scanf("%d", &num); sum += num; } printf("%d\n", sum); if(t > 0){ printf("\n"); } } return 0; }唯一需要说明的是最后一次输出不应有空行。

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Test Comment.

明显是可以的= =。。